英文数学题（概率）ThX for help!!
I think something is wrong with the problem. no key to the problem therefor choose A
at most 47 had breakfast. 12 had eggs bacon and toast
4 eggs and toast 3 had bacon and toast 7 had eggs and bacon
total 23 eggs 22 bacon 19 toast 4eggs ang 17toast were rest A guest is selected at random only eggs and toast no bacon eliminate C,D and B therefor choose A
数学概率问题，英文的
a) 3/(3+7)=3/10
b)junior's name on the second draw : 7/10×3/10+3/10×8/10=9/20
junior's name on the second draw and a sophomore's name was drawn first:7/10×3/10=21/100
(21/100)/(9/20)=7/15
c) junior's name on the second draw : 7/10×3/10+3/10×8/10=9/20
A junior's name on the second draw and a junior's name was drawn first: 3/10×8/10=6/25
(6/25)/(9/20)=8/15
d)7/10×7/10=49/100
e) 3/10×8/10=6/25
f) 7/10×3/10+3/10×2/10=27/100
PS:楼上的你given 没有翻译....而且是大二生不是高中生....
一道概率题目，请懂英语的人帮忙做。
很简单，A和C
英语数学题，有关概率的independent event
(i) and (iii) only.
That is that E is the answer.