而今哥哥们对相关于1-3/y²=为什么呢究竟是怎么回事？，哥哥们都想要分析一下1-3/y²=，那么语蓉也在网络上收集了一些对相关于1y.的一些信息来分享给哥哥们，太令人意外了，哥哥们一起来简单了解下吧。
1/2(x² - y)+1/3(x - y²)+1/6(x²+y²) 搜狗问问原式=1/2x²-1/2y+1/3x-1/3y²+1/6x²+1/6y²=2/3x²-1/2y+1/3x-1/6y²
(1)y=3x²+10x-8 顶点式:y=3(x+5/3)²-49/3 两根式:y=(3x-2)(x+4)y=-5x²+9x+6 顶点式:y=-5(x-9/10)²+201/20 两根式:y=[x+(-9+√201)/10][x+(-9-√201)/10]
求微分方程通解或特解 y\" - 3y'²=0,x=0y=1,1 搜狗问问令y'=p(y),y''=(dp/dy)(dy/dx)=(dp/dy)p 原方程化为:y^3*(dp/dy)p-1=0,分离变量得:pdp=dy/y^3 两边积分得:1/2p^2=-(1/2)y^(-2),即p^2=-1/y^2+c1 则(dy/dx)^2=c1-1/y^2 .
1、x³ - y³ - x² - xy - y² 2、(x²+x+1)(x²+x+2) - 6 搜狗问问1、 x³-y³-x²-xy-y² =(x³-y³)-(x²+xy+y²) =(x-y)(x²+xy+y²) -(x²+xy+y²) =(x-y-1)(x²+xy+y²) 2、 (x²+x+1)(x²+x+2)-6 =(x²+x+1)[(x²+x+1)+1]-6 =(x²+x+1)²+(x²+.
(1)1 - x²+2xy - y² (2)x² - y² - z² - 分解因式 谢谢 搜狗问问(1)1-x²+2xy-y² =1-(x-y)² =(1-x+y)(1+x-y) (2)x²-y²-z²-2yz =x²-(y+z)² =(x+y+z)(x-y-z)
1.分解因式: (x²+y²)³+(z² - x²)³ - (y²+z²)³令a=x^2+y^2 b=z^2-x^2 则y^2+z^2=a+b 所以原式=a^3+b^3-(a+b)^3 =a^3+b^3-a^3-3a^2b-3ab^2-b^3 =-3ab(a+b) =-3(x^2+y^2)(z^2-x^2)(y^2+z^2) =-3(x^2+y^2)(z+x)(z-x)(y^2+z^2)
1.把下列各式分解因式:(1)x³y+3x - 2²y² - 6y;(2)x²z+.(1)x³y+3x-2x²y²-6y; =(x³y+3x)-(2x²y²+6y) =x(x²y+3)-2y(x²y+3) =(x²y+3)(x-2y) (2)x²z+x²-y²-y²z =(x²z+x²)-(y²+y²z) =x²(z+1)-y²(z+1) =(z+1)(x²-y²) =(z+1)(x+y)(x-y) (3)ab(c²+d²)+cd(a²+b²) =abc²+abd²+a²cd+b²cd =abc²+a²cd +abd²+b²cd =ac(bc+ad)+bd(ad+bc) =(bc+ad)(ac+bd) ;(4)x²-6xy+9y²-3x+9y =(x-3y)²-3(x-3y) =(x-3y)(x-3y-3)
化简再求值[(x²+y²)² - 4x²y²]÷(x² - y²)原式=(x^4+2x²y²+y^4-4x²y²)/(x²-y²) =(x^4-2x²y²+y^4)/(x²-y²) =(x²-y²)²/(x²-y²) =x²-y² =4-4/9 =32/9
y=x² - ax+b,数集A{x/x - y=0},数集B{x/y - ax=0}.由A x-y=0 y-x=0 x²-(a+1)x+b=0 根为x=-3或x=1 所以 b=-3*1=-3 a+1=-3+1=-2 a=-3 y=x²+3x-3 对于B y-ax=0 y+3x=0 x²+3x-3+3x=0 x²+6x=3 (x+3)²=12 x+3=±√12 x=-3±2√3 所以 B={-3+2√3,-3-2√3}
一个多项式加上3x²y - 3xy²得3x三次方减y的三次方,求这.所以这个多项式是3x³-y³) =3x³设为A A+(3x²y-3xy²-3x²y+3xy²-3x²y+3xy²-y³-y³ 则A=3x³-y³-(3x²y-3xy²)=3x³
这篇文章到这里就已经结束了，希望对哥哥们有所帮助。