1) F(A,B,C,D) = BC + D + D'(B'+C')(AD+B) = BC + D + (B'+C')(AD+B) = BC + D + AB'D+BB'+AC'D+BC' = B(C+C') + D(1 + AB'+AC') = B + D

F=A'BC+A'B'+A'C'=A'(BC+B'+C')=A'[BC+(BC)']=A'

(1)化简函数Y2=∑m(0,1,2,3,4,5,8,10,11,12).,数字电路与逻辑设计问题 Y2=∑m(0,1,2,3,4,5,8,10,11,12)= ∑m(0,1,2,3)+ ∑m(0,4,8,12)+ ∑m(0,1,4,5)+∑m(2,3,11,12)=A'B'+C'D'+A'C'+B'C (2)CD\AB 00 01 11 1000 0 1 0 101 1 1 0 011 1 1 1 010 1 1 0 1 画卡诺图,得到逻辑表达式为 F=A'B+A'D+A'C+BCD+AB'D'

是的,有的为了方便这样写就打个＂'＂,代表非的意思.有的时候在上面加一个横杠也代表非的意思.

F1 = AB'+A'B+A = A(B'+1)+A'B= 1 F2 = AB'C'+ABC+AB'C+ABC'+A'B = AB'+AB+A'B=A+A'B=A+B F3 = A'+B'+C'+D' +ABCD = (ABCD)'+ABCD=1 F4 = AB+A'C+BC+A+C' = (AB+A)+A+C+C'= 1 A⊕0 = A'0+A0' = 0+A= A-----------根据异或的定义 A⊕1 = A'1+A1' =A'+0 = A' A⊕A=AA'+A'A = 0 A⊕A' = A'A' + AA = A'+A =1

化简:F(A,B,C,D)=BC+D+D'(B'+C')(AD+B) =BC+D+D'(AB'D+AC'D+BB'+BC') =BC+D+BC'D' =BC+D+BC' =B+D 而题目中的 BC+D+BC'D' 还可以继续化简: =BC+D+BC'=B(C+C')+D=B+D 下面介绍几个公式:1. D+D'X=D+X (1) 2. D'+DY=D'+Y (2)3. X+X'=1 (3)4. XX'=0 (4) 等等.最后得到化简结果为:F(A,B,C,D) = B + D

(1)A与非A等于0 ,0加任何数都得0

2B

Y=AB + AC' + B'C + BC' + B'D + BD' +ADE(F + G)=A(B'C)'+B'C + BC' + B'D + BD' +ADE(F + G)=A+B'C + BC' + B'D + BD' +ADE(F + G)=A+B'C + BC' + B'D + BD'

F(A,B,C)=A'B+B'C+B'C'=A'B+B'(C+C')=A'B+B'=A'+B' F(A,B,C)=A'B+B'C+B'C'=∑m(2,3)+∑m(1,5)+∑m(0,4)=∑m(0,1,2,3,4,5)=∑m(0,1,2,3)+∑m(0,1,4,5)=A'+B'