求助大神一道数据结构的编程题,C语言编程,用顺序表实现,蟹蟹蟹蟹!! 顺序表的建立及遍历

9885℃ MIKE

求助大神一道数据结构的编程题,C语言编程,用顺序表实现,蟹蟹蟹蟹!!顺序表的建立及遍历

求数据结构顺序表c语言实现.....

无函数版本,只需你写算法就OK,算是比较基础的··*顺序表的基本操作*/

#include <stdio.h>

#include <conio.h>

#include <stdlib.h>

#define LIST_INIT_SIZE 10

#define LISTINCREMENT 3

#define TRUE 1

#define FALSE 0

#define OK 1

#define ERROR -1

#define OVERFLOW -2

typedef int Status;

typedef int ElemType;

typedef struct {

int *elem;

int length;

int listsize;

}SqList;Status Initlist_Sq(SqList &L) /*初始化顺序表*/

{

}int Destroylist(SqList &L) /*销毁顺序表*/

{

}int Clearlist_Sq(SqList &L) /*清空顺序表*/

{

}

Status Listempty_Sq(SqList L) /*测试顺序表是否为空*/

{

}Status ListInsert_Sq(SqList &L, int i,ElemType e) /*在第i个位置上插入一个元素*/

{ }int LocateElem_Sq(SqList L,ElemType e) /*返回元素e在顺序表中的位置*/

{

}Status ListDelete_Sq(SqList &L, int i, int &e) /*删除第i个位置上的元素*/

{ }void Print_Sq(SqList L) /*输出顺序表*/

{ int i;

if (Listempty_Sq(L))

printf("\nSequential List's length is %d. It's empty!",L.length);

else

printf("\nSequential List's length is %d. These element are : ",L.length);

for(i=0;i<L.length;i++)

printf(" %d",L.elem[i]);

}

void menu()

{ printf("\n");

printf("\n* * * * * * * * * * * * * * * * * * * * * * * * * *\n");

printf(" 1 ------- Print the Sequential List(输出顺序表).\n");

printf(" 2 ------- Insert a data in the Sequential List(在第i个位置上插入一个元素).\n");

printf(" 3 ------- Delete a data in the Sequential List(删除第i个位置上的元素).\n");

printf(" 4 ------- Get a element's locationt in the SqList(返回元素e在顺序表中的位置).\n");

printf(" 5 ------- Clear the Sequential List(清空顺序表).\n");

printf(" 6 ------- Exit.\n");

printf("* * * * * * * * * * * * * * * * * * * * * * * * * *\n");

printf("\n");

}void menuselect(SqList L)

{ int k,i,done=1;

ElemType e;

while (done)

{ menu();

printf("Please choose: ");

scanf("%d",&k);

getchar();

switch(k)

{ case 1: Print_Sq(L); break;

case 2:{

printf("\nInput the location and data you want to Insert: ");

scanf("%d,%d",&i,&e);

if (ListInsert_Sq(L,i,e)==ERROR) printf("Insert location is not correct!\n");

break;

} case 3:{ printf("\nInput the location you want to delete data: ");

scanf("%d",&i);

if (ListDelete_Sq(L,i,e)==ERROR)

printf("Delete location is not exit!\n");

else

printf("\nDelete data is %d.",e);

break; }

case 4:{ printf("\nInput the data you want to find: ");

scanf("%d",&e);

if (LocateElem_Sq(L,e)!=FALSE)

printf("\nData %d location in the Sequential List is %d.", e,LocateElem_Sq(L,e));

else printf("\nData %d is not in the Sequential List.\n", e);

break; }

case 5: Clearlist_Sq(L);; break;

case 6: done=0;

}

}

}

void main()

{ ElemType e;

SqList La;

int n,i;

Initlist_Sq(La);

printf("Input a number of the element in the Sequential List (n<=%d):",LIST_INIT_SIZE);

scanf("%d",&n);

printf("Enter these elements:");

for(i=1;i<=n;i++)

{scanf("%d",&e);<br> ListInsert_Sq(La,i,e);}

menuselect(La);

getch();

}

c语言数据结构题,,顺序表

初始化一个头结点head,然后比较list1,和list2链表的第一个节点,选择比较小的连接到head上去,如此往复。

#include "stdafx.h"

#include<iostream>

#include<queue>

using namespace std;

typedef struct node{

        int data;

        struct node *next;

}Node,*List;

List createList(int N,int multi)

{

List head = (List)malloc(sizeof(Node));

head->data = 0;

head->next=NULL;

int count = 0;

List p = head;

while(count<N)

{count++;

List s = (List)malloc(sizeof(Node));

s->data = count*multi;

s->next = NULL;

p->next = s;

p = s;

}

return head;

}

void traverse(List head)

{

if(head == NULL)

{

return;

}

List p = head->next;

while(p)

{

cout<<p->data<<" ";

p = p->next;

}

cout<<endl;

}

List unionList(List list1,List list2)

{

if(list1 == NULL||list1->next==NULL)

return list2;

if(list2 == NULL||list1->next==NULL)

return list1;

list1 = list1->next;

list2 = list2->next;

List head = (List)malloc(sizeof(Node));

List p = NULL;

if(list1!=NULL && list2!=NULL)//初始化第一个节点

{

if(list1->data<=list2->data)

{

head->next = list1;

list1 = list1->next;

}else{

head->next = list2;

list2 = list2->next;

}

}

p = head->next;

while(list1!=NULL && list2!=NULL)//主体部分

{

if(list1->data<=list2->data)

{

p->next = list1;

list1 = list1->next;

p = p->next;

}else{

p->next = list2;

list2 = list2->next;

p = p->next;

}

}

while(list1 != NULL)//如果list2已经完了,list1还有剩余

{

p->next = list1;

list1 = list1->next;

p = p->next;

}

while(list2 != NULL)//如果list1已经完了,list2还有剩余

{

p->next = list2;

list2 = list2->next;

p = p->next;

}

return head;

}

int main()

{

int N = 10;

List head1 = createList(N,1);

List head2 = createList(N,2);

traverse(head1);

traverse(head2);

List head = unionList(head1,head2);

traverse(head);

    getchar();

    return 0;

}

数据结构(用C语言描述)编程题求助!!!

这是个二叉排序树例题,希望对你有帮助! #include "stdio.h" # include "stdlib.h" struct Bnode {int data; struct Bnode *lchild,*rchild; }; void insertbst(Bnode *&t, Bnode *s) {if (t== NULL) t=s; else if (s->data< t->data) insertbst(t-> lchild,s); else insertbst(t-> rchild,s); } void inorder(Bnode *t) { if (t!=NULL) { inorder(t->lchild); printf("%d ", t->data); inorder(t->rchild); } } void main() {int i,x; Bnode *t=NULL,*s; for (i=1;i<=4;i++) {scanf("%d",&x); s=( Bnode *)malloc(sizeof(Bnode)); s->data=x; s-> lchild= NULL; s-> rchild= NULL; printf("\n"); insertbst(t,s); } inorder( t); printf("\n"); }

求大神!!!急急急!!!用C语言数据结构算法编写程序!!!!!!!!

#include 

#include 

#include 

#define LEN sizeof(stacknode)

typedef struct stacknode

{

    char data;

    struct stacknode *next;

}stacknode;

typedef struct

{

    stacknode *top;

}LinkStack;

int precedence(char c)

{

    switch (c)

    {

        case '#':return 0;

        case '+':return 1;

        case '-':return 1;

        case '*':return 2;

        case '/':return 2;

        case '(':return 3;

        case ')':return 0;

        default :return printf("\nError:preccedence函数内输入错误!输入了:%c\n",c);

    }

}

void InitStack(LinkStack *s)

{

    s->top=NULL;

}

int PUSH(LinkStack *s,char d)

{

    stacknode *t;

    t=(stacknode*)malloc(LEN);

    //if((t=(stacknode*)malloc(LEN))==NULL)return 0;

    t->data=d;

    t->next=s->top;

    s->top=t;

    return 1;

}

int Top(LinkStack *s,char *x)

{

    stacknode *p;

    if(s->top==NULL)return 0;

    p=s->top;

    s->top=p->next;

    *x=p->data;

    free(p);

    return 1;

}

void Clear(LinkStack *s)

{

    stacknode *p,*q;

    p=s->top;

    free(s);

    while(p)

    {

        q=p->next;

        free(p);

        p=q;

    }

}

int Topshow(LinkStack *s,char *c)

{

    stacknode *p;

    if(s->top==NULL)return 0;

    p=s->top;

    *c=p->data;

    return 1;

}

int deep(LinkStack *s)

{

    int i=0;

    stacknode *p;

    p=s->top;

    while(p)

    {

        i++;

        p=p->next;

    }

    return i;

}

int oprate(int a,int b,char c)

{

    switch (c)

    {

        case '+':return a+b;

        case '-':return a-b;

        case '*':return a*b;

        case '/':return a/b;

        default: printf("\nError:oprate函数内输入错误!输入了:'%c'\n",c);

    }

}

int main(void)

{

    char ch[500],op[]="+-*/#()[]{}";

    LinkStack *s1,*s2;

    s1=(LinkStack*)malloc(sizeof(LinkStack));

    s2=(LinkStack*)malloc(sizeof(LinkStack));

    InitStack(s1);

    InitStack(s2);

    while(~scanf("%s",ch))

    {

        int i,l=strlen(ch)+1;

        char c;

        ch[l-1]='#';

        PUSH(s1,'#');

        for(i=0;i

        {

            int k,key,j;

            char c1,c2;

            for(k=0,key=0;i='0';i++,key=1)

                k=ch[i]-'0'+k*10;

            if(key)

            {

                i--;

                printf("%d\n",k);

                PUSH(s2,k);

            }

            else

            {

                char c;

                int n=precedence(ch[i]);

                Topshow(s1,&c);

                while(n<=precedence(c)&&c!='(')

                {

                    char a,b;

                    Top(s1,&c);

                    if(c=='#')

                    {

                        PUSH(s1,'#');

                        break;

                    }

                    Top(s2,&b);

                    Top(s2,&a);

                    printf("%d%c%d=%d\n",a,c,b,oprate(a,b,c));

                    PUSH(s2,oprate(a,b,c));

                    Topshow(s1,&c);

                    if(c=='('&&ch[i]==')')

                    {

                        Top(s1,&c);

                        break;

                    }

                }

                if(ch[i]!=')')PUSH(s1,ch[i]);

            }

        }

        Topshow(s2,&c);

        printf("%d\n",c);

    }

    return 0;

}这个 只能进行char级数值(中间过程及结果不得出现127以上的数)的运算,写的很麻烦,楼主多给点分吧。。。

多给要int级数值、加括号的也可以写。。