y=(2x² - 1)³,求导

y=cos(2x²+1) y'=-4xsin(2x²+1)

分解因式y²(x² - 2x)³+y²

y²(x²-2x)³+y²=y²【(x²-2x)³+1】=y²(x²-2x+1)【(x²-2x)²-(x²-2x)+1】=y²(x-1)²(x^4-4x³+4x²-x²+2x+1)

求 微分方程y＂+y'=2x²+1的通解

特征方程为:x^2-1=0, 得特征根为1,-1得:y1=c1e^x+c2e^(-x)令特解y*=(ax+b)e^(2x)y* '=(2ax+a+2b)e^(2x)y* ＂=(4ax+4a+4b)e^(2x)代入原方程得:3ax+4a+3b=x, 得:3a=1, 4a+3b=0, 解得:a=1/3, b=-4/9因此通解y=y1+y*=c1e^x+c2e^(-x)+(x/3-4/9)e^(2x)

( - 2x²y³)² (xy)³ 计算

(-2x²y³)² (xy)³=(-2)²x⁴y^6*x³y³=4x^(4+3)*y^(6+3)=4x^7y^9 【中学生数理化】团队为您答题.很高兴为您解答,祝你学习进步!有不明白的可以追问!若对您有帮助,请点击下面的【选为满意回答】按钮,谢谢!

设y=2x - cosx2,求dy

dy=2+2xsinx² dx

已知y=X³+ln³,求y的导数.

y'=3x^2+(3ln^2x)/x

y=(2x³ - 3x²+6x)²求导

y=(2x³-3x²+6x)² y'=2(2x³-3x²+6x)*(2x³-3x²+6x)' =2(2x³-3x²+6x)*(6x²-6x+6) =12(2x³-3x²+6x)(x²-x+1)

y=2x+cosx的单调区间是?

函数的定义域为r(观察可得),把函数求导:y'=2-sinx;因为2-sinx>0恒成立,所以函数的单调递增区间为r.

已知2X - Y=0求(X² - Y²/X³+Y³)/[(X - Y)²/(X+Y)³]带过程

2X-Y=0Y=2X[(X²-Y²/(X³+Y³)]/[(X-Y)²/(X+Y)³]=[(X-Y)(X+Y)/(X+Y)(X²-XY+Y²)/[(X-Y)²/(X+Y)³]=[(X-Y)/(X²-XY+Y²)/[(X-Y)²/(X+Y)³]=(X-Y)/(X²-XY+Y²)*(X+Y)³/(X-Y)²=1/(X²-XY+Y²)*(X+Y)³/(X-Y)=(X+Y)³/(X²-XY+Y²)(X-Y)=(X+2X)³/(X²-X*2X+4X²)(X-2X)=(3X)³/(3X²)(-X)=(3X)³/(-3X³)=27X³/(-3X³)=-9

设y=x²cosx, 求dy 望高手指教

1.求由方程e^y=x^2siny+cosx所确定的隐约数y=y(x)的微分dy两边同时对x求导,得:e^y*dy=2xsiny+x^2*cosy*dy-sinx(e^y-x^2*cosy)dy=2x*siny-sinx dy=(2x*siny-sinx)/(e^y-x^2*cosy) 2.设函数y=e^(x^2),求y''/x=0 y'=e^(x^2)*2xy''=e^(x^2)*2x*2x+2e^(x^2) =(4x^2+2)*e^(x^2)当x=0时,y''=2